Question

杭电ACM水题求助。。。

Input contains multiple test cases. The first line of the input is a single integer T (0<T<1000) which is the number of test cases. T test cases follow. Each test case contains a char C (+,-,*, /) and two integers A and B(0<A,B<10000).Of course, we all know that A and B are operands and C is an operator.
For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.

#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
int n;
cin>>n;
while(n)
{
char c;
int a;
int b;
cin>>c>>a>>b;
switch(c)
{
case '+':cout<<a+b<<endl;
break;
case '-':cout<<a-b<<endl;
break;
case '*':cout<<a*b<<endl;
break;
case '/':
{
if(a/b==(double)a/b)
{
cout<<a/b<<endl;
}
else if(a/b!=(double)a/b)
{
cout<<fixed<<setprecision(2)<<(double)a/b<<endl;
}
break;
}
}
n--;
}
}
想问一下我的程序哪里出错了？按样例输出都是对的..

Answer 1

晕 都没有明白我的意思

我是说：感觉水题都不怎么好做
想听听各位做水题的感受

最好给点建议：怎么才能入门