根号计算题求助，谢谢。
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let
u=(20x+20)^(1/3)
[20x+(20x+20)^(1/3) ]^(1/3) =20
20x+(20x+20)^(1/3) =8000
(20x+20) +(20x+20)^(1/3) - 8020 =0
u^3 + u -8020 =0
(u-20)(u^2 + (1/20)u +401) =0
u=20
=>
(20x+20)^(1/3) =20
20x+20 =8000
20x=7980
x=399
u=(20x+20)^(1/3)
[20x+(20x+20)^(1/3) ]^(1/3) =20
20x+(20x+20)^(1/3) =8000
(20x+20) +(20x+20)^(1/3) - 8020 =0
u^3 + u -8020 =0
(u-20)(u^2 + (1/20)u +401) =0
u=20
=>
(20x+20)^(1/3) =20
20x+20 =8000
20x=7980
x=399
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谢谢I
谢谢
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