
4-(2/3×5/7÷2/3×7/5+7/3)括号?
2个回答
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4-(2/3×5/7÷2/3+7/3)
=4-(2/3÷2/3)×5/7-7/3
=4-(2+1/3)-5/7
=4-2-(1/3+5/7)
=2-(7/21+15/21)
=42/21-22/21
=20/21
=21分之20
=4-(2/3÷2/3)×5/7-7/3
=4-(2+1/3)-5/7
=4-2-(1/3+5/7)
=2-(7/21+15/21)
=42/21-22/21
=20/21
=21分之20
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