Question

-3a的6次方乘a的三次方加4a的平方乘a的7次方减5a的9次方等于多少？

Answer 1

计算结果为：-3a^{6}\cdota^{3}+4a^{2}\cdota^{7}-5a^{9} = -3a^{9}+4a^{9}-5a^{9} = -4a^{9}−3a6\cdota3+4a2\cdota7−5a9=−3a9+4a9−5a9=−4a9

Answer 2

-3a^6×a^3+4a^2×a^7-5a^9
=-3a^9+4a^9-5a^9
=-4a^9