Question

pb 取日期问题

如何取当前日期前二个月的1号

Answer 1

string ls_date
date ld_today
long ll_year,ll_month
ld_today=date(today())
ll_year=year(ld_today)
ll_month=month(ld_today)
choose case ll_month
case 1
ls_date=string(ll_year - 1)+"-"+string(11)+"-01"
case 2
ls_date=string(ll_year - 1)+"-"+string(12)+"-01"
case 3 to 12
ls_date=string(ll_year)+"-"+string(ll_month - 2)+"-01"
end choose
return ls_date