
解方程|3(x-1)+2|=0.5|5x+1|
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if (5x+1)>= 0, 6x-2 = 5x +1, x=3, OK
if 3(x-1)<= 0, -6x+2 = -(5x +1), x=3, not a true root
if 3(x-1)<=0<= (5x+1), 6x-2 = -(5x +1), x = 1/11, ok
taken together
x =3 or x = 1/11
if 3(x-1)<= 0, -6x+2 = -(5x +1), x=3, not a true root
if 3(x-1)<=0<= (5x+1), 6x-2 = -(5x +1), x = 1/11, ok
taken together
x =3 or x = 1/11

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计算过程如下:首先,计算4个数值的和:∑Xs = 0.3 + 0.2 + 0.4 + 0.1 = 1然后,计算 lg-1(∑Xs/4):lg-1(∑Xs/4) = lg-1(1/4) = -1其中,lg表示以10为底的对数,即 log10。...
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