Question

java下如何求数组中最大的那个数并求其下标

Answer 1

public class A
{
public static void main(String[] args)
{
int[] num={3,2,8,5,7,6};
int temp=num[0];
int len=0;
for(int i=0;i<num.length;i++)
{
if(temp<num[i])
{
temp=num[i];
len=i;
}
}
System.out.println("最大值为:"+temp+",下标为:"+len);
}
}

Answer 2

public class NumberApp {

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);

Integer[] numArray = getNumbers(sc);
if (numArray.length > 0) {
NumberUtils nums = new NumberUtils(numArray);
System.out.println("Numbers input: " + nums);
System.out.println("The average is " + nums.getAverage());
System.out.println("The maximum is " + nums.getMax());
System.out.println("The minimum is " + nums.getMin());
} else {
System.err.println("No numbers were input");
}
}

private static Integer[] getNumbers (Scanner sc) {

ArrayList<Integer> numbers = new ArrayList<Integer>();

while (sc.hasNextInt()){
numbers.add(sc.nextInt());
}

return numbers.toArray(new Integer[0]);
}

}

//这是第一个class，下面那个是另一个class

import java.util.*;

public class NumberUtils {

private Integer[] nums;

public NumberUtils(Integer[] nums) {
this.nums = nums;
}

public double getAverage() {
double sum = 0;
for (int i = 0; i < nums.length; i++) {
sum += nums[i]; // this is an example of auto-unboxing
}
return sum/nums.length;
}
/**
* 求数组中最大值的
*/
public int getMax() {
int max = 0;
for (int i =0; i <nums.length;i++){
if (nums[i]>max)
max = nums[i];
}

return max;
}

public int getMin() {
int min = nums[0];
for (int i =1; i <nums.length;i++){
if (nums[i]<min)
min = nums[i];
}

return min;
}
public String toString() {
return Arrays.toString(nums);
}

}

Answer 3

有更简单的方法。。
数组可以用java给我们的sort方法先排序，然后用一个中间值index保存数组名.length，然后输出index就可以了