Question

一道初三二次根式题目,急!

已知a-b=(2根号3)-1,ab=根号3,求(a+1)(b-1)的值.

在线等,大家帮帮忙,请写下过程,谢谢.

Answer 1

(a+1)(b-1)= ab - a + b - 1

= ab - (a - b) - 1

= 根号3 - 2根号3 + 1 - 1

= -根号3

Answer 2

(a+1)(b-1)=ab-(a-b)-1=根号3-2根号3-1-1=-2

Answer 3

(a+1)(b-1)=ab-(a-b)-1=根号3-(2根号3-1)-1=-根号3

Answer 4

(a+1)(b-1)=-(a-b)+ab-1=-(2根号3-1）+根号3-1=-根号3