1/3+1/6+1/10+1/15+1/21+1/28+1/36+1/45=? (算式中都是分数)怎样用简便方法计算?
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应该把项都拆开 例如1/21=1/首银3-1/7 都拆开之后 整理 应该者羡宴有规律 你试试哈派橡
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1/3+1/6+1/10+1/15+1/21+1/28+1/36+1/45
=2(1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90
=2[1/(2*3)+1/(3*4)+1/(4*5)+1/(5*6)+1/(6*7)+1/(7*8)+1/(8*9)+1/(9*10)]
=2[(3-2)/(2*3)+(4-3)/(3*4)+(5-4)/(4*5)+(6-5)/(5*6)+(7-6)/(6*7)+(8-7)/(7*8)+(9-8)/(8*9)+(10-9)/(9*10)]
=2{[3/(2*3)-2/(2*3)]+[4/(3*4)-3/(3*4)]+[5/(4*5)-4/(4*5)]+[6/(5*6)-5/(5*6)]+[7/(6*7)-6/(6*7)]+[8/(7*8)-7/(7*8)]+[9/(8*9)-8/(8*9)]+[10/(9*10)-9/(9*10)]}
=2(1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/橘悔燃7+1/7-1/8+1/8-1/9+1/圆虚9-1/前坦10)
=2(1/2-1/10)
=4/5
=2(1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90
=2[1/(2*3)+1/(3*4)+1/(4*5)+1/(5*6)+1/(6*7)+1/(7*8)+1/(8*9)+1/(9*10)]
=2[(3-2)/(2*3)+(4-3)/(3*4)+(5-4)/(4*5)+(6-5)/(5*6)+(7-6)/(6*7)+(8-7)/(7*8)+(9-8)/(8*9)+(10-9)/(9*10)]
=2{[3/(2*3)-2/(2*3)]+[4/(3*4)-3/(3*4)]+[5/(4*5)-4/(4*5)]+[6/(5*6)-5/(5*6)]+[7/(6*7)-6/(6*7)]+[8/(7*8)-7/(7*8)]+[9/(8*9)-8/(8*9)]+[10/(9*10)-9/(9*10)]}
=2(1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/橘悔燃7+1/7-1/8+1/8-1/9+1/圆虚9-1/前坦10)
=2(1/2-1/10)
=4/5
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1/3+1/6+1/10+1/15+1/21+1/28+1/36+1/45= 0.8
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=(1/2-1/雀运碰3)*2+(1/悄笑3-1/顷谈4)*2+(1/4-1/5)*2+.....+(1/9-1/10)*2
=(1/2-1/3+1/3-1/4+1/4-1/5+....+1/9-1/10)*2
=(1/2-1/10)*2
=4/10*2
=4/5
=(1/2-1/3+1/3-1/4+1/4-1/5+....+1/9-1/10)*2
=(1/2-1/10)*2
=4/10*2
=4/5
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