Question

php中学习Ajax时$_POST 取不到值？

showCities.php：
<script type="text/javascript" language="javascript">
var myXmlHttpRequest="";
function getXmlHttpObject(){
var xmlHttpRequest;
if(window.ActiveXobject){
xmlHttpRequest=new ActiveXobject("Microsofe.XMLHTTP");
}else{
xmlHttpRequest=new XMLHttpRequest();
}
return xmlHttpRequest;
}

function getCities(){
myXmlHttpRequest=getXmlHttpObject();
if(myXmlHttpRequest){
var url="/ajax/showCitiesPro.php";
var data="province="+$('sheng').value;
myXmlHttpRequest.open("post",url,true);
myXmlHttpRequest.setRequestHeader("Content-Type","applcation/x-www-form-urlencoded");
myXmlHttpRequest.onreadystatechange=chuli;
myXmlHttpRequest.send(data);
}

}
function chuli(){
if(myXmlHttpRequest.readyState==4){
if(myXmlHttpRequest.status==200){
window.alert(myXmlHttpRequest.responseXML);
}
}
}
function $(id){
return document.getElementById(id);
}
</script>
showCitiesPro.php：
<?php
header("Content-Type: text/xml;charset=utf-8");
$province=$_POST['province'];
echo "接收到数据是";
?>
window.alert(myXmlHttpRequest.responseXML);为null，这是为什么？
还有响应的显示
<br />
<b>Deprecated</b>: Automatically populating $HTTP_RAW_POST_DATA is deprecated and will be removed in a future version. To avoid this warning set 'always_populate_raw_post_data' to '-1' in php.ini and use the php://input stream instead. in <b>Unknown</b> on line <b>0</b><br />
<b>Notice</b>: Undefined index: province in <b>E:\phpEnv\www\ajax\showCitiesPro.php</b> on line <b>7</b><br />

Answer 1

你也没有把$province的值输出啊，怎么就能确定没接收到值呢？

echo "接收到数据是"; 应该改成 echo "接收到数据是".$province;

追问

如果得到值得话
window.alert(myXmlHttpRequest.responseXML)会输出XML对象

同时我也帮得到的数据放进log里
file_put_contents("e:/mylog.log",$province."\r\n",FILE_APPEND);
也没有出现值