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已知复数z1=1?3i,若复数z满足条件(|z1|+z)?z1=1,则z=______
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∵z1=1?
i,∴|z1|=
=2,
故(|z1|+z)?z1=1可化为:(2+z)?z1=1,
所以z=
?2=
?2=
?2
=
3 |
12+(?
|
故(|z1|+z)?z1=1可化为:(2+z)?z1=1,
所以z=
1 |
z1 |
1 | ||
1?
|
1+
| ||||
(1?
|
=
1+
|