Question

MSP430G2553单片机一个用计时器输出PWM的程序

要求是按一下点亮灯，然后越来越亮，十次后越来越暗，循环此过程。 我的问题是，我用定时器写的延时函数用来防抖，只要一用这个函数，不管怎么按按钮灯都不亮，只要不使用这个函数防抖，程序功能就能实现。真的不知道哪错了。。求大神指点，代码如下

#include "MSP430G2553.h"
void GPIO_Init(); //GPIO初始化函数
void Timer_A_Init();
void BCS_Init();
int key = 0;
unsigned int keydown = 0;
int main(void) {
WDTCTL = WDTPW + WDTHOLD; // Stop WDT
GPIO_Init();
BCS_Init();
TACTL |= MC_1 + TASSEL_2;
TACCTL1 = OUTMOD_7;
TACCR0 = 512 - 1;
_EINT();
while (1) {
if (key < 11) {
TACCR1 = 512/10*key ;
} else {
TACCR1 = 512 / 10 * (20 - key);
}
};
}
void GPIO_Init() //GPIO初始化函数
{
P1DIR |= BIT6; //设定P1.0,P1.6为输出
P1OUT |= BIT6; //设定P1.0的值
P1SEL |= BIT6;
P1REN |= BIT3; //启用内部上下拉电阻
P1OUT |= BIT3; //将电阻设为上拉
P1DIR &= ~BIT3; //P1.3设为输入（可省略）
P1IES |= BIT3; //P1.3设为下降沿中断
P1IE |= BIT3; //允许中断
}
#pragma vector = PORT1_VECTOR
__interrupt void PORT1_ISR(void) {
Timer_A_Init();
}
void Timer_A_Init() {
TA1CTL = TASSEL_2 + MC_1 + TACLR; //SMCLK、下降沿触发、定时器清零
TA1CCR0 = 10000; //10ms
TA1CCTL0 |= CCIE;
}
#pragma vector=TIMER1_A0_VECTOR
__interrupt void Timer_A0_ISR(void) {
if (((P1IN & BIT3)==0)&&key<20){
key++;
}
if (((P1IN & BIT3)==0)&&key>=20){
key = 0;
}
}
void BCS_Init() {
BCSCTL1 = CALBC1_1MHZ;
DCOCTL = CALDCO_1MHZ;
BCSCTL2 &= ~SELS;
}

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Answer 1

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