Question

JAVA读取以下XML文件中所有ITEM节点下的信息

<OUTPUT>
<ITEM>
<gmsfhm></gmsfhm>
<result_gmsfhm>一致</result_gmsfhm>
</ITEM>

<ITEM>
<xm></xm>
<result_xm>一致</result_xm>
</ITEM>

<ITEM>
<xp>/99/</xp>
</ITEM>

</OUTPUT>

Answer 1

org.w3c.dom
dom4j

Answer 2

//该方法需要引用的包有
//import org.jdom.*;
//import java.util.*;

public void test(){
InputStream ins = null;
try {
ins = new FileInputStream("E:\\test.xml");

} catch (Exception e) {
e.printStackTrace();
}
Document doc = null;
DOMBuilder domB = new DOMBuilder();
try
{
doc = domB.build(ins);
}
catch (JDOMException ex)
{
ex.printStackTrace();
}
List list = doc.getRootElement().getChildren("ITEM");
//这里可以取到指定顺序的节点 也可以循环处理
Element ele = (Element)list.get(1).getChilde("result_gmsfhm");
System.out.println(ele.getText());
}

Answer 3

dom,sax,dom4j都可以啊！