解方程，求过程，谢谢
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ab-2a+2b=-1 => 6ab-12a+12b=-6
bb+12a+6b=15 =>bb+6b+9+12a=24 =>(b+3)^2+12a=24, 设：b+3=c
6ab+bb+18b=9 =>b(6a+b+18)=9
cc+12a=24=>a=(24-cc)/12
(c-3)((24-cc)/2+c-3+18)=9 =>(c-3)(27-cc/2+c)=9
27c-ccc/2+cc-81+1.5cc-3c-9=0=>-ccc/2+2.5cc+24c-90=0
=>c=-6.5423,8.1780,3.3643=>b=-9.5423,5.1780,0.3643,代入a=(15-bb-6b)/12再求a
bb+12a+6b=15 =>bb+6b+9+12a=24 =>(b+3)^2+12a=24, 设：b+3=c
6ab+bb+18b=9 =>b(6a+b+18)=9
cc+12a=24=>a=(24-cc)/12
(c-3)((24-cc)/2+c-3+18)=9 =>(c-3)(27-cc/2+c)=9
27c-ccc/2+cc-81+1.5cc-3c-9=0=>-ccc/2+2.5cc+24c-90=0
=>c=-6.5423,8.1780,3.3643=>b=-9.5423,5.1780,0.3643,代入a=(15-bb-6b)/12再求a
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