Question

xfire集成spring开发webservice怎么配置发布地址

Answer 1

1.首先建一个Web工程，引入相应的jar包，Xfire开发最精简jar包下载
服务器端：
commons-logging-1.1.1.jar
jdom-1.0.jar
org.springframework.aop-3.1.1.RELEASE.jar
org.springframework.asm-3.1.1.RELEASE.jar
org.springframework.beans-3.1.1.RELEASE.jar
org.springframework.context-3.1.1.RELEASE.jar
org.springframework.core-3.1.1.RELEASE.jar
org.springframework.expression-3.1.1.RELEASE.jar
org.springframework.web.servlet-3.1.1.RELEASE.jar
org.springframework.web-3.1.1.RELEASE.jar
wsdl4j-1.6.1.jar
xfire-all-1.2.6.jar

客户端：
com.springsource.org.junit-4.7.0.jar
commons-codec-1.3.jar
commons-httpclient-3.0.jar
commons-logging-1.1.1.jar
jdom-1.0.jar
wsdl4j-1.6.1.jar
xfire-all-1.2.6.jar
XmlSchema-1.1.jar

2.修改web.xml，加入以下代码：

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<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>

<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<servlet>
<servlet-name>xfireServlet</servlet-name>
<servlet-class>org.codehaus.xfire.spring.XFireSpringServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>xfireServlet</servlet-name>
<url-pattern>/service/*</url-pattern>
</servlet-mapping>
3.在classpath下加入Spring配置文件applicationContext.xml，加入以下代码：

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<context:component-scan base-package="my.webservice" />

<!-- XFire start -->
<import resource="classpath:org/codehaus/xfire/spring/xfire.xml" />
<bean id="webAnnotations" class="org.codehaus.xfire.annotations.jsr181.Jsr181WebAnnotations" />
<bean id="jsr181HandlerMapping" class="org.codehaus.xfire.spring.remoting.Jsr181HandlerMapping">
<property name="xfire" ref="xfire" />
<property name="webAnnotations" ref="webAnnotations" />
</bean>
<!-- XFire end -->
4.定义WebService接口，添加相应注解：

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@WebService
public interface IBookService {

@WebMethod
public Book getBook();
}
5.接口实现类，注解中serviceName定义发布的服务名，endpointInterface定义实现的接口：

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@Component
@WebService(serviceName="BookService",
endpointInterface = "my.webservice.IBookService")
public class BookServiceImpl implements IBookService {

@Override
public Book getBook() {

Book b = new Book(1, "Java核心思想", 100);

System.out.println(">>>>>>Server: " + b);

return b;
}
}
6.以上便是服务端的配置及实现，是不是很简单。把工程发布到Tomcat并启动，在浏览器中输入：http://127.0.0.1:8080/XFireTest/service/BookService?wsdl（BookService为上面serviceName定义的名称），如果浏览器中显示BookService相关xml信息，则表示WebService发布成功。
7.客户端调用服务端方法：
(1)使用接口调用，此方法需要发布服务者提供接口，或我们自己通过wsdl生成接口。自己生成接口方法：
wsimport -keep -p my.client http://127.0.0.1:8080/XFireTest/service/BookService?wsdl
-keep 指示保留生成的文件，-p 指定需要在其中生成构件的包名称。http://127.0.0.1:8080/XFireTest/service/BookService?wsdl 是WSDL文件的位置。
wsimport在JAVA_HOME/bin目录下，应该已加到path环境变量中，可直接在cmd中运行以上命令，注意先进入要生成类的目录（如src）再执行。

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@Test
public void testBookService() {
Service serviceModel = new ObjectServiceFactory().create(IBookService.class);
String url = "http://127.0.0.1:8080/XFireTest/service/BookService";
IBookService service = null;

try {
service = (IBookService) new XFireProxyFactory().create(serviceModel, url);
Book b = service.getBook();
System.out.println(">>>>>>>>Client: " + b);
} catch (Exception e) {
e.printStackTrace();
}
}
(2)通过wsdl调用，该方法如果返回值是String可正常使用，如果像本列中返回Book类型，则打印值为[#document: null]，返回类型是org.apache.xerces.dom.DocumentImpl，需手动解析。我在项目中使用时，发布服务的时候把数据用xml形式返回，客户端用dom4j解析。

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@Test
public void wsdlTest() throws MalformedURLException, Exception {
Client client = new Client(new URL("http://127.0.0.1:8080/XFireTest/service/BookService?wsdl"));
Object[] results = client.invoke("getBook", new Object[] {});
System.out.println(results[0]);
}

Answer 2

给你个简单的例子吧

<?xml version="1.0" encoding="UTF-8"?>  
<beans   
    xmlns="

    xmlns:xsi="

    xmlns:jaxws="

    xsi:schemaLocation="   
        

        

        

        

  
    <import resource="classpath:META-INF/cxf/cxf.xml"/>   
    <import resource="classpath:META-INF/cxf/cxf-servlet.xml"/>
    
    
    <!-- jaxws:server示例  首先在web.xml中添加servlet
        <servlet>
            <servlet-name>CXFService</servlet-name>
            <servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
        </servlet>
    
        <servlet-mapping>
            <servlet-name>CXFService</servlet-name>
            <url-pattern>/deviceWService/*</url-pattern>
        </servlet-mapping>
    
    
        <jaxws:server id="androidWService"  serviceClass="webservice注解的服务类"  address="/访问路径">   
                <jaxws:serviceBean/>   
        </jaxws:server>
    -->
    
    <jaxws:server id="androidWService"  serviceClass="com.my.project.plugin.webservice.MyWebservice"  address="/ddd">   
              
    </jaxws:server>
</beans>

 

@WebService
public class MyWebservice {

    public String ddd() {
        return "MyWebservice";
    }
}