Question

关于PHP的ftp_put报错

错误信息：ftp_put() expects parameter 4 to be long

我用类写了个FTP上传的代码，其他都正常，就这个上传出错了，有高手能帮我就揪出错误吗？

共3个网页文件，index.htm上传的，upload.php，ftp_upload.php（类）

######### upload.php ##############
<?php
$myfile = $_FILES['myfile'];
include("../myclass/ftp_upload.php");
$myftp = new myftp();
$myftp->ftp_pasv_mode='TRUE';
$myftp->ftp_connect_host='203.195.150.104';
$myftp->ftp_connect_port='9421';
$myftp->ftp_login_username='10064814-1013677-myftptest';
$myftp->ftp_login_userpassword='1234';
$myftp->ftp_upload_file=$myfile['tmp_name'];
$myftp->ftp_upload_target=$myfile['name'];
$myftp->ftp_upload_mode='FTP_BINARY';
$myftp->upload();
?>

######### ftp_upload.php ############
<?php
class myftp {
var $ftp_connect_host;
var $ftp_connect_port;
var $ftp_login_username;
var $ftp_login_userpassword;
var $ftp_upload_target;
var $ftp_upload_file;
var $ftp_upload_mode;
var $ftp_pasv_mode;

function upload() {
$con = ftp_connect($this->ftp_connect_host,$this->ftp_connect_port);
$login = ftp_login($con,$this->ftp_login_username,$this->ftp_login_userpassword);
$openpasv = ftp_pasv($con,$this->ftp_pasv_mode);
$ftpupload = ftp_put($con,$this->ftp_upload_target,$this->ftp_upload_file,$this->ftp_upload_mode);

if($con) {echo 'con success</br>';}else{ echo 'con fail';return false;}
if($login) {echo 'login success</br>';}else{ echo 'login fail';return false;}
if($openpasv) {echo 'pasv success</br>';}else{ echo 'pasv fail';return false;}
if($ftpupload) {echo 'upload success</br>';}else{ echo 'upload fail';return false;}
ftp_close($con);
}
}
?>

Answer 1

$myftp->ftp_upload_mode='FTP_BINARY';

取消'引号
$myftp->ftp_upload_mode=FTP_BINARY;

追问

嗯嗯！昨晚试了下，成功解决问题了！那么这个FTP_BINARY不需要加引号呢？它不是一个字符串来的吗？

追答

是预设整型常量，不是字符串...