数学,这两题怎么写???
2个回答
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4.
∫[(2x-1)/(x²-5x+6)]dx
=∫[5/(x-3) -3/(x-2)]dx
=5∫[1/(x-3)]d(x-3) -3∫[1/(x-2)]d(x-2)
=5ln|x-3| -3ln|x-2| +C
5.
∫[0:π/2][(x+sinx)/(1+cosx)]dx
=½∫[0:π/2](x·sec²½x)dx +∫[0:π/2][sinx/(1+cosx)]dx
=∫[0:π/2]xd(tan½x) -ln|1+cosx||[0:π/2]
=xtan½x|[0:π/2]-∫[0:π/2]tan½xdx -(0-ln2)
=π/2 -0 +2ln|cos½x||[0:π/2]+ ln2
=π/2 +2[ln(√2/2) -0] +ln2
=π/2
∫[(2x-1)/(x²-5x+6)]dx
=∫[5/(x-3) -3/(x-2)]dx
=5∫[1/(x-3)]d(x-3) -3∫[1/(x-2)]d(x-2)
=5ln|x-3| -3ln|x-2| +C
5.
∫[0:π/2][(x+sinx)/(1+cosx)]dx
=½∫[0:π/2](x·sec²½x)dx +∫[0:π/2][sinx/(1+cosx)]dx
=∫[0:π/2]xd(tan½x) -ln|1+cosx||[0:π/2]
=xtan½x|[0:π/2]-∫[0:π/2]tan½xdx -(0-ln2)
=π/2 -0 +2ln|cos½x||[0:π/2]+ ln2
=π/2 +2[ln(√2/2) -0] +ln2
=π/2
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