Question

求大神可以帮忙编译一个C语言程序。输入一个8位数。输出前四位的和除以后四位的和。下面是我自己写的。

int num[10];
for (i = 1; i <= 8; i++) {
scanf("%d", &num[i]);
}
double calculate = (double)(num[1] + num[2] + num[3] + num[4]) / (num[5] + num[6] + num[7] + num[8]);
printf("%g\n", calculate);

Answer 1

#include<stdio.h>
#include<stdlib.h>
void c(void)
{
    char ch;
    while((ch=getchar())!='\n'&&ch!=EOF);
}
int main()
{
    int num;

    while(1)
    {
        while(1)
        {
            printf("input a number of 8 bit:");
            scanf("%d",&num);
            c();
            if(num<10000000||num>99999999)
            {
                printf("input err!\n");
                continue;
            }
            else
                break;
        }
        printf("high 4 bit:%4d\nlow 4 bit:%4d\nresult:%f\n",num/10000,num%10000,((float)(num/10000))/(num%10000));
    }
    return 0;
}