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(3) dy = y'dx = [(√x)'/(1-x)]dx = {(1/(2√x)]/(1-x)}dx = dx/[2(1-x)√x]
(5) 定义域 (1-x^3) > 0, 则 y = (1/2)ln(1-x^3)
dy = y'dx = [(1/2)(1-x^3)'/(1-x^3)]dx = [(-3/2)x^2/(1-x^3)]dx
(5) 定义域 (1-x^3) > 0, 则 y = (1/2)ln(1-x^3)
dy = y'dx = [(1/2)(1-x^3)'/(1-x^3)]dx = [(-3/2)x^2/(1-x^3)]dx
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