Question

1、编写一个函数求n!，然后利用该函数计算1！+2！+3！+…+n！的值。

Answer 1

#include<stdio.h>
main()
{

int
n,i,j,sum1,sum=0,gongzi,hundred,fifty,ten,five,two,one;

scanf("%d",&n);

for(i=1;i<=n;i++)

{

sum1=1;

for(j=1;j<=i;j++)

{

for(j=1;j<=i;j++)

{

sum1=sum1*j;

}

printf("%d的阶乘为%d\n",j-1,sum1);

}

sum=sum+sum1;

}

printf("1到%d的阶乘和sum=%d\n",n,sum);

scanf("%d",&gongzi);

hundred=gongzi/100;

fifty=gongzi%100/50;

ten=gongzi%100%50/10;

five=gongzi%100%50%10/5;

two=gongzi%100%50%10%5/2;

one=gongzi%100%50%10%5%2/1;

//printf("%d元分别要一百元、五十元、十元、五元、二元和一元的抄票数为:\n%d,
%d,
%d,
%d,
%d,
%d\n",gongzi,hundred,fifty,ten,five,two,one);

printf("%d元工资有:\n",gongzi);

if(hundred!=0)

{

printf("%d张百元,
",hundred);

}

if(fifty!=0)

{

printf("%d张五十元,
",fifty);

}
if(ten!=0)

{

printf("%d张十元,
",ten);

}
if(five!=0)

{

printf("%d张五元,
",five);

}
if(two!=0)

{

printf("%d张二元,
",two);

}
if(one!=0)

{

printf("%d张一元\n",one);

}
}