定积分从一个区间换到另一个区间?
这个题他的区间是怎么来的,为什么要令x=二分之派-t,还有函数怎么变了。数学小白希望各位大佬解答一下谢谢!!!我会积极采纳...
这个题他的区间是怎么来的,为什么要令x=二分之派-t,还有函数怎么变了。数学小白希望各位大佬解答一下谢谢!!!我会积极采纳
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I = 4∫[0, π]cos^4 x dx
= 8∫[0, π/2]cos^4 x dx
x = π/2 - t
dx = -dt
I = 8∫[π/2, 0] cos^4 (π/2 - t) d(π/2 - t)
= 8∫[0, π/2] sin^4 t dt
= 8∫[0, π/2] sin^4 x dx
不定积分的公式
1、∫ a dx = ax + C,a和C都是常数
2、∫ x^a dx = [x^(a + 1)]/(a + 1) + C,其中a为常数且 a ≠ -1
3、∫ 1/x dx = ln|x| + C
4、∫ a^x dx = (1/lna)a^x + C,其中a > 0 且 a ≠ 1
5、∫ e^x dx = e^x + C
6、∫ cosx dx = sinx + C
7、∫ sinx dx = - cosx + C
8、∫ cotx dx = ln|sinx| + C = - ln|cscx| + C
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I = 4∫[0, π]cos^4 x dx
= 8∫[0, π/2]cos^4 x dx (by symmetry)
x = π/2 - t
dx = -dt
I = 8∫[π/2, 0] cos^4 (π/2 - t) d(π/2 - t)
= 8∫[0, π/2] sin^4 t dt (co-function property and switching lower limit and upper limit)
= 8∫[0, π/2] sin^4 x dx (change t to x)
= 8∫[0, π/2]cos^4 x dx (by symmetry)
x = π/2 - t
dx = -dt
I = 8∫[π/2, 0] cos^4 (π/2 - t) d(π/2 - t)
= 8∫[0, π/2] sin^4 t dt (co-function property and switching lower limit and upper limit)
= 8∫[0, π/2] sin^4 x dx (change t to x)
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