Question

C语言 浮点数转换为字符串

#include <stdio.h> #include <stdlib.h> #include <string.h> char c_je[51]; char* zh(double x ) /*数字金额转换为大写金额子程序*/ { int i,n,bz; char je[14]; char temp[13]; char f1[10][3]={"零","壹","贰","叁","肆","伍", "陆","柒","捌","玖"}; /*数字对应的大写数组变量*/ char f2[11][3]={"亿","仟","佰","拾","万", "仟","佰","拾","元","角","分"}; /*每位数字对应单位数组变量*/ sprintf(je,"%.01f",100*x); n=strlen(je); //printf("%d GGGGG",n); c_je[0]='\0'; bz=1; for(i=0;i<n;i++) { strcpy(temp,&je[i]); if(atoi(temp)==0) { bz=2; if(i==0) strcat(c_je,f1[0]); break; } if(je[i]!='0') { if(bz==0) strcat(c_je,f1[0]); //printf("%s ++++",f1[je[i]-'0']); strcat(c_je,f1[je[i]-'0']); bz=1; strcat(c_je,f2[13-n+i]); } else { if(n-i==7&&(je[i-1]!='0'||je[i-2]!='0'||je[i-3]!='0')) strcat(c_je,"万"); if(n-i==3) strcat(c_je,"元"); bz=0; } } if(bz==2) { if(n-i>=7 && n-i<10) strcat(c_je,"万"); if(n-i>=3) strcat(c_je,"元"); strcat(c_je,"正"); } return c_je; } main() { zh(1234.56); } 请问 strcat(c_je,f1[je[i]-'0']);里面f1[je[i]-'0']为什么要-‘0’ je[i]-'0'是什么意思

Answer 1

je[i]存的是一个字符型数据的ASCII码，比如'1'会被存为49
'0'的ASCII码为48，所以49-48正好就是整数类型的1