X(6X+12)=90
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x(6x+12)=90
解: 6x²+12x=90
x²+2x-15=0
(x+5)(x-3)=0
x=-5或x=3
解: 6x²+12x=90
x²+2x-15=0
(x+5)(x-3)=0
x=-5或x=3
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X(6X+12)=90
6X^2 + 12X = 90
6X^2 + 12X - 90 = 0
Dividing by 6, we get:
X^2 + 2X - 15 = 0
Factoring the left side, we get:
(X + 5)(X - 3) = 0
So the solutions are:
X = -5 or X = 3.
However, we should check both solutions to see if they are valid:
If X = -5, then 6X + 12 = -18, and X(6X+12) = (-5) x (-18) = 90, so this is a solution.
If X = 3, then 6X + 12 = 30, and X(6X+12) = 3 x 30 = 90, so this is also a solution.
Therefore, the solutions are X = -5 or X = 3.
6X^2 + 12X = 90
6X^2 + 12X - 90 = 0
Dividing by 6, we get:
X^2 + 2X - 15 = 0
Factoring the left side, we get:
(X + 5)(X - 3) = 0
So the solutions are:
X = -5 or X = 3.
However, we should check both solutions to see if they are valid:
If X = -5, then 6X + 12 = -18, and X(6X+12) = (-5) x (-18) = 90, so this is a solution.
If X = 3, then 6X + 12 = 30, and X(6X+12) = 3 x 30 = 90, so this is also a solution.
Therefore, the solutions are X = -5 or X = 3.
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