Question

解答数学题一道，好心人帮忙下

已知函数f(x)=1/x^2-1,求f(-3),f(-2),f(0)
希望大家可以帮到我

Answer 1

f(x)=x平方分之1-1
解：定义域为：x≠0,y≤0
f(－3)=（－3）平方分之1－1＝－9分之8
f(－2）＝1／（－2）²－1＝－3／4
f（0）无解

Answer 2

x=0 y=2

Answer 3

f(-3)=1/(-3)^2-1
=-8/9

f(-3)=1/(-2)^2-1
=-3/4

f(-3)=1/(0)^2-1
无解

Answer 4

x=-3, f(x)=f(-3)=-8/9

x=-2, f(x)=f(-2)=-3/4

x=0, f(x)=f(0)=无穷大

Answer 5

f(x)=1/(x^2-1)
则f(-3)=1/[(-3)^2-1]=1/8
f(-2)=1/[(-2)^2-1]=1/3
f(0)=1/[(0)^2-1]=-1