Question

用C#编写，输入一个整数将其各位数字颠倒顺序后输出

Answer 1

不难，告诉您最容易理解的方法，相信您自己可以做的！

将整型转换为字符串数组
反向循环读出每个字符并且合并到一个新的字符串变量中
将新的字符串类型转化为整型后输出

Answer 2

static void Main(string[] args)
{
string ddd = Console.ReadLine();
char[] strarr = ddd.ToString().ToCharArray();
StringBuilder sb = new StringBuilder();
for (int i = strarr.Length-1; i >=0; i--)
{
sb.Append(strarr[i]);
}
Console.WriteLine(sb.ToString());
Console.ReadKey();
}

Answer 3

static void Main(string[] args)
{
string str;
Console.WriteLine("请输入任何一个字符串：");
str=Console.ReadLine();
char[] c = str.ToCharArray();
Array.Reverse(c);
foreach (char cc in c)
{
Console.Write(cc);
}
Console.ReadKey();
}

Answer 4

int n = 123;
for (int i = n.ToString().Length-1; i >=0; i--) {
string s = n.ToString().Substring(i,1);
Console.Write(s);
}

Answer 5

static
void
Main(string[]
args)
{
string
ddd
=
Console.ReadLine();
char[]
strarr
=
ddd.ToString().ToCharArray();
StringBuilder
sb
=
new
StringBuilder();
for
(int
i
=
strarr.Length-1;
i
>=0;
i--)
{
sb.Append(strarr[i]);
}
Console.WriteLine(sb.ToString());
Console.ReadKey();
}