Question

java小程序运行出来说明为什么？

public interface Valuable {
public double getMoney();
}

interface Protectable {
public void beProtected();
}

interface A extends Protectable {
void m();
}

abstract class Animal {
private String name;

abstract void enjoy();
}
class GoldenMonkey extends Animal implements Valuable,Protectable {
public double getMoney() {return 100000;}

public void beProtected() {
System.out.println("live in the room");
}

public void enjoy(){}

public void test() {
GoldenMonkey v = new GoldenMonkey();
v.getMoney();
Protectable p = (Protectable)v;
p.beProtected();
}
}

class Hen implements A {
public void m(){}
public void beProtected(){}
}

Answer 1

没主方法怎么运行啊

Answer 2

是没有
public state void main(String []args){
}

还是你代码没有复制全

Answer 3

你没有函数入口main

Answer 4

楼主把主方法拿来，这样没有规则。