Question

计算 (x^8+y^8)(x^4+y^4)(x^2+y^2)(x+y)(x-y)

这题怎么做 谁能帮帮我 谢谢大家了 快

Answer 1

先做后两项
（x+y)(x-y)=x^2-y^2
依次向前做
最后得x^16-y^16

Answer 2

从后往前算！
(x^8+y^8)(x^4+y^4)(x^2+y^2)(x+y)(x-y)
=(x^8+y^8)(x^4+y^4)(x^2+y^2)(x^2-y^2)
=(x^8+y^8)(x^4+y^4)(x^4-y^4)
=(x^8+y^8)(x^8-y^8)
=x^16-y^16

Answer 3

(x^8+y^8)(x^4+y^4)(x^2+y^2)(x+y)(x-y)
=(x^8+y^8)(x^4+y^4)(x^2+y^2)(x^2-y^2)
=(x^8+y^8)(x^4+y^4)(x^4-y^4)
=(x^8+y^8)(x^8-y^8)
=x^16-y^16

Answer 4

从后往前算..

Answer 5

x^16-y^16