Question

如何计算啊。。。。。求解！！（log底数4真数3+log底数8真数3）乘（log底数3真数2+log底数9真数2）=？

要求具体过程，谢谢！

Answer 1

(log4 3 +log8 3 )*(log3 2 +log9 2 )
=((1/2)*log2 3+(1/3)*log2 3)*(log3 2+(1/3)*log3 2)
=(5/6)log2 3 *(4/3)log3 2
=(5/6)*（4/3）
=10/9