Question

java中Scanner的方法调用

import java.util.Scanner;
public class CompareTwoNumbers1
{
double number1,number2;
Scanner scanner;
public CompareTwoNumbers1()
{
System.out.println("请输入两个数字:")；
scanner=new Scanner(代码1);//实例化一个Scanner对象；
number1=代码2; //从键盘输入一个整数赋值给number1；
number2=代码3；//从键盘输入一个整数赋值给number2；
System.out.println("较大的数值是："代码4)；//将number1和number2中较大值输出；
}
public static void main(String args[])
{
CompareTwoNumbers1 ct=new CompareTwoNumbers1();
System.exit(0);
}
}
四个代码应该怎么处理，代码4中，Scanner调用什么方法可以取得最大值？

Answer 1

//我给补全了,两个数值比较用Math类的max(double,double)方法

import java.util.Scanner;

public class CompareTwoNumbers1 {
double number1, number2;
Scanner scanner;

public CompareTwoNumbers1() {
System.out.println("请输入两个数字:");
scanner = new Scanner(System.in);// 实例化一个Scanner对象；
number1 = scanner.nextDouble(); // 从键盘输入一个整数赋值给number1；
number2 = scanner.nextDouble();// 从键盘输入一个整数赋值给number2；
System.out.println("较大的数值是：" + Math.max(number1, number2));// 将number1和number2中较大值输出；
}

public static void main(String args[]) {
CompareTwoNumbers1 ct = new CompareTwoNumbers1();
System.exit(0);
}
}

Answer 2

scanner= new Scanner(System.in);
number1=scanner.nextDouble();
number2=scanner.nextDouble();
System.out.println("较大的数值是："+Math.max(number1,number2) );

Answer 3

Scanner没有这种方法吧~

System.out.println("较大的数值是："+(Double.parseDouble(number1+"")>Double.parseDouble(number2+"")?Double.parseDouble(number1+""):Double.parseDouble(number2+"")));//将number1和number2中较大值输出；

Math.max(double double)也不错啊；~

Answer 4

Scanner scanner = new Scanner(System.in);
String string = scanner.nextLine();

Answer 5

1.System.in
2.scanner.nextInt()
3.scanner.nextInt()
4.+Math.max(number1,number2)