Question

急急急！Java高手请帮帮忙！

class Test implements Runnable
{
String str;
public void Test(String str)
{
this.str=str;
}

public void run()
{
try
{

for (int i=0;i<10;i++)
{
Thread.sleep(10);
}

if(getName().equals("thread3"))
{
System.out.println("thread3" + "is runing");
}
else
{
System.out.println("thread4" + "is runing");
}

}
catch (InterruptedException e)
{
}
}
}
public class test
{

public static void main(String args[])
{

Test t3= new Test();
Test t4= new Test();
Thread t = new Thread(t3);
Thread t1 = new Thread(t4);

t.start();
t1.start();
System.out.println("******the programe is running******");

}
}

上面的程序中，if(getName().equals("thread3"))老是说找不到符号，是怎么回事，麻烦告诉下，要改好的程序，谢谢！主要是用runnable来实现线程！

Answer 1

兄弟，你的构造方法好像写错了，你提出的问题找不到符号是因为你没有定义过getName（）这个方法。帮你改了下：
class Test implements Runnable {
String str;

public Test(String str) {
this.str = str;
}

public String getName() {
return str;
}

public void run() {
try {

for (int i = 0; i < 10; i++) {
Thread.sleep(10);
}

if (this.getName().equals("thread3")) {
System.out.println("thread3" + "is runing");
} else {
System.out.println("thread4" + "is runing");
}

} catch (InterruptedException e) {
}
}
}

public class Test3 {

public static void main(String[] args) throws Exception {

Test t3 = new Test("thread3");
Test t4 = new Test("thread4");
Thread t = new Thread(t3);
Thread t1 = new Thread(t4);

t.start();
t1.start();
System.out.println("******the programe is running******");

}
}
结果为：
****the programe is running******
thread3is runing
thread4is runing

Answer 2

无参构造方法呢？
还有你这里默认的getName（）可以得到thread3吗
Returns:
the name of the class or interface represented by this object
可以自己写一个覆盖原有的getName（）

Answer 3

你的getName方法在哪定义的。。。。

Answer 4

你把if(getName().equals("thread3"))改成if(Thread.currentThread()=="thread3")就OK了