Question

ajax联动框的问题

父节点的信息怎么删除 一直重复
var ajax = null;
function getCity(province_id){
ajax = createAjax();
ajax.onreadystatechange=function(){
if(ajax.readyState == 4){
if(ajax.status == 200){
var cities = ajax.responseXML.getElementsByTagName("city");
$("#city").length = 0;
var myoption = document.createElement("option");
myoption.value = "";
myoption.innerText = "--请选择章节--";

$("city").remove();
$("#city").append($(myoption));
for(var i=0;i<cities.length;i++){
var city_id = cities[i].childNodes[0].childNodes[0].nodeValue;
var city_name = cities[i].childNodes[1].childNodes[0].nodeValue;
var myoption = document.createElement("option");
myoption.value = city_id;
myoption.innerText = city_name;
$("#city").append($(myoption));

Answer 1

alert一下你的cities里到底是什么东西