Question

一个继承BaseAdapter的类，怎么启动一个AlertDialog

我做一个demo，界面是ListView，每个item上都有一个按钮，所以自己写了一个继承BaseAdapter的类，我在getView里面是这么写的 可是每次点击button都会崩掉，提示我 new AlertDialog.Builder(context).setTitle("").setMessage("").show();出错，求大虾帮忙啊

Answer 1

1)mListView = (ListView) findViewById(R.id.listView);
mListView.setAdapter(new mListAdapter(this, getdata2()));
//设置Adapter的时候，用this传Context，不要用getApplicationContext()

2)public mListAdapter(Context context, List<HashMap<String, Object>> list) {
this.mContext = context;
this.mHashMaps = list;
}//将Context传入自定义Adapter中

3)private void ShowInfo() {
new AlertDialog.Builder(mContext).setTitle("my listview").setMessage("introduce....").
setPositiveButton("OK", new DialogInterface.OnClickListener() {

@Override
public void onClick(DialogInterface dialog, int which) {
// TODO Auto-generated method stub

}
}).show();
}//这样Builder(mContext)就OK了

Answer 2

progressDialog = ProgressDialog.show(this, getResources().getString(R.string.main_dialog_init), getResources() .getString(R.string.main_dialog_content), true);