展开全部
不全是。依据传入的参数决定调用哪种算法。
看源码:至少涉及了dijkstra、广度优先/深度优先算法。
if source is None:
if target is None:
## Find paths between all pairs.
if weight is None:
paths=nx.all_pairs_shortest_path(G)
else:
paths=nx.all_pairs_dijkstra_path(G,weight=weight)
else:
## Find paths from all nodes co-accessible to the target.
directed = G.is_directed()
if directed:
G.reverse(copy=False)
if weight is None:
paths=nx.single_source_shortest_path(G,target)
else:
paths=nx.single_source_dijkstra_path(G,target,weight=weight)
# Now flip the paths so they go from a source to the target.
for target in paths:
paths[target] = list(reversed(paths[target]))
if directed:
G.reverse(copy=False)
else:
if target is None:
## Find paths to all nodes accessible from the source.
if weight is None:
paths=nx.single_source_shortest_path(G,source)
else:
paths=nx.single_source_dijkstra_path(G,source,weight=weight)
else:
## Find shortest source-target path.
if weight is None:
paths=nx.bidirectional_shortest_path(G,source,target)
else:
paths=nx.dijkstra_path(G,source,target,weight)
追问
这个没包含source确定,arget不确定的情况哦?
追答
可能是我贴的有问题,其实源码中是配对的(从1开始数,第4个else和第1个if配对)。建议自行查看源码,可以用wingIDE4.1,非常方便。另这里贴出的是networkx.shortest_paths.shortest_path方法的源码,另有networkx.shortest_path方法(使用标准的BFS)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询