Question

opengl 旋转立方体

#include<GL/glut.h>
#include<stdio.h>
#include<math.h>

int oldmx=0;
int oldmy=0;
int oldmz=0;
int newx=0;
int newy=0;
int newz=0;
int cos_ankle=0;

void Mouse(int button,int state,int x,int y)
{
if(state==GLUT_DOWN)
oldmx=x,oldmy=y;
}

void onMouseMove(int x,int y)
{
int newx=x,newy=y;
}

void myDisplay()
{
glClear(GL_COLOR_BUFFER_BIT|GL_DEPTH_BUFFER_BIT);

cos_ankle=((oldmx*newx+oldmy*newy)/sqrt(((double)oldmx*(double)oldmx+(double)oldmy*(double)oldmy)*((double)newx*(double)newx+(double)newy*(double)newy)));
glRotatef(acos((double)cos_ankle),0,0,10);
glBegin(GL_QUADS);
glColor3f(1.0,0.0,0.0);
//前
glVertex3f(-0.5,-0.5,0.5);
glVertex3f(-0.5,0.5,0.5);
glVertex3f(0.5,0.5,0.5);
glVertex3f(0.5,-0.5,0.5);
//后
glVertex3f(-0.5,-0.5,-0.5);
glVertex3f(-0.5,0.5,-0.5);
glVertex3f(0.5,0.5,-0.5);
glVertex3f(0.5,-0.5,-0.5);
//左
glVertex3f(-0.5,-0.5,-0.5);
glVertex3f(-0.5,0.5,-0.5);
glVertex3f(-0.5,0.5,0.5);
glVertex3f(-0.5,-0.5,0.5);
//右
glVertex3f(0.5,-0.5,0.5);
glVertex3f(0.5,0.5,0.5);
glVertex3f(0.5,0.5,-0.5);
glVertex3f(0.5,-0.5,-0.5);
//上
glVertex3f(-0.5,0.5,0.5);
glVertex3f(-0.5,0.5,-0.5);
glVertex3f(0.5,0.5,-0.5);
glVertex3f(0.5,0.5,0.5);
//下
glVertex3f(-0.5,-0.5,-0.5);
glVertex3f(-0.5,-0.5,0.5);
glVertex3f(0.5,-0.5,0.5);
glVertex3f(0.5,-0.5,-0.5);
glEnd();
glFlush();
}

int main(int argc, char *argv[])
{
glutInit(&argc, argv);
glutInitDisplayMode(GLUT_RGB | GLUT_SINGLE);
glutInitWindowPosition(100, 100);
glutInitWindowSize(400, 400);
glutCreateWindow("第一个OpenGL程序");
glutIdleFunc(myDisplay);
glutMouseFunc(Mouse);
glutMotionFunc(onMouseMove);
glutDisplayFunc(&myDisplay);
glutMainLoop();
return 0;
}

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Answer 1

这个东西并不是太难的,你可以: 定义一个矩形区域范围,为实现点击鼠标左键来实现自由移动颜色条的功能 ... 然后你通过这个点的坐标来判断,此点是否在该区域内,如果是的,则自由移动颜色条,否则是立方体的自由旋转...

追问

你好，我写的这个程序能运行，但不显示立方体。你能不能帮我看看那里出问题了