Question

求用C语言编程 输出 123456789 1234567 12345 123 1这样的三角形

如下：

1
123
12345
1234567
123456789
4444444
33333
222
1

1
21
321
4321
54321
6543
765
87
9

123456789
1234567
12345
123
1

1
12
123
1234
12345
3456
567
78
9

要设计这四个程序，请问该怎样写？
谢谢！

Answer 1

我用最笨的方法写的 编译通过（不通过就没天理了！！）但很有效

代码如下：

#include <stdio.h>

#include <stdlib.h>

main()

{

      printf("    1\n");

      printf("   123\n");

      printf("  12345\n");

      printf(" 1234567\n");

      printf("123456789\n");

      printf(" 4444444\n");

      printf("  33333\n");

      printf("   222\n");

      printf("    1\n");

      printf("              \n");

      printf("              \n");

      printf("1\n");

      printf("21\n");

      printf("321\n");

      printf("4321\n");

      printf("54321\n");

      printf("6543\n");

      printf("765\n");

      printf("87\n");

      printf("9\n");

      printf("            \n");

      printf("            \n");

      printf("123456789\n");

      printf(" 1234567\n");

      printf("  12345\n");

      printf("   123\n");

      printf("    1\n");

      printf("                \n");

      printf("                \n");

      printf("    1\n");

      printf("   1 2\n");

      printf("  1 2 3\n");

      printf(" 1 2 3 4\n");

      printf("1 2 3 4 5\n");

      printf(" 3 4 5 6\n");

      printf("  5 6 7\n");

      printf("   7 8\n");

      printf("    9\n");

      system("pause");

}

Answer 2

RtlStringCchPrintfW这个API可以替换字符串,你要求的是形状吧?自己画下吧,反正有规律的,原型在下面:
RtlStringCchPrintfW(
OUT LPWSTR pszDest,
IN size_t cchDest,
IN LPCWSTR pszFormat,
...
);
...是你要替换成的东西！
实例在下面：
WCHAR pszDest[30];
size_t cchDest = 30;

LPCWSTR pszFormat = L"%s %d + %d = %d.";
WCHAR* pszTxt = L"The answer is";

NTSTATUS status =
RtlStringCchPrintfW(pszDest, cchDest, pszFormat, pszTxt, 1, 2, 3);
输出的结果是："The answer is 1 + 2 = 3."
%d就是你要替换的地方！

Answer 3

C语言编程．很难做吗

Answer 4

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