Question

数学两道解方程，要具体的解的过程，最好写下来，谢谢，急急急

Answer 1

(2x-1)/3=(2x-3)/4 -1
解：
(2x-1)/3=(2x-3)-4/4
(2x-1)*4 =(2x-3-4)*3
(2x-1)*4 =(2x-7)*3
8x-4 =6x-21
8x-6x-4=-21
2x-4=-21
2x=-21+4
2x=-17
x=-17/2

（0.04x+0.9)/0.5-(x-1)/2=(0.03+0.0.2x)/0.03
解：
{（0.04x+0.9)*2 -（x-1）*0.5} /0.5*2=(0.03+0.0.2x)/0.03
{（0.04x+0.9)*2 -（x-1）*0.5} /1=(0.03+0.0.2x)/0.03

（0.04x+0.9)*2 -（x-1）*0.5=(0.03+0.0.2x)/0.03
0.08x+1.8-(0.5x-0.5)=(0.03+0.0.2x)/0.03
0.08x+1.8-0.5x+0.5=(0.03+0.0.2x)/0.03
0.08x+1.8-0.5x+0.5=(0.03+0.0.2x)/0.03
2.3-0.42x=(0.03+0.0.2x)/0.03
(2.3-0.42x)*0.03=0.03+0.0.2x
(2.3-0.42x)*0.03=0.03+0.0.2x
0.069-0.0126x=0.03+0.0.2x
0.069-0.03=0.0126+0.0.2x
0.039=0.0716x
X=0.5446927374