初中数学,求解,急急急!!!
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3、(1)原式
=(x²-y²)/(x-y)-2x²/(x-y)
=-(x²+y²)/(x-y)
(2)原式
=[(m+n)(m-n)/(m+n) ]▪[m(m-n)/(m-n)²]
=m
(3)原式
=[a/(a+1) ] ▪[(a+1)(a-1)/(a-1)]
=a
(4)原式
=[(x²-1-8)/(x+1)]▪(x+1)/(x+3)
=[(x+3)(x-3)/(x+1)]▪(x+1)/(x+3)
=x-3
=(x²-y²)/(x-y)-2x²/(x-y)
=-(x²+y²)/(x-y)
(2)原式
=[(m+n)(m-n)/(m+n) ]▪[m(m-n)/(m-n)²]
=m
(3)原式
=[a/(a+1) ] ▪[(a+1)(a-1)/(a-1)]
=a
(4)原式
=[(x²-1-8)/(x+1)]▪(x+1)/(x+3)
=[(x+3)(x-3)/(x+1)]▪(x+1)/(x+3)
=x-3
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