Question

ajaxFileUpload可以同时多个input file控件一起上传吗

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Answer 1

　　——————jsp页面代码————————————————————
<form action="doUpload" method="post" enctype="multipart/form-data">
<table id="mytb">
<tr>
<td><input type="file" name="upload" id="upload" value=""></td>
<td><input type="button" name="del" id="del" value="删除"
onclick="delRow(this)" style="display: display;"></td>
</tr>
</table>
<input type="button" name="add" id="add" value="继续添加"
onclick="addRow()"> <input type="submit" value="上传">
</form>
————————js代码————————————————————————
<script type="text/javascript">
function addRow() {
var table = document.getElementById("mytb");//获取表格对象
if (table.rows.length > 9) {
alert("不能再加了，最多上传10个附件");
} else {
var tr = table.insertRow();//为表格增加行
var td1 = tr.insertCell();//为行增加单元格
var td2 = tr.insertCell();
td1.innerHTML = "<input name='upload' type='file' id='upload'/>";//为单元格增加内容
td2.innerHTML = "<input type='button' name='del' id='del' value='删除' onclick='delRow(this)'>";
}
}

function delRow(obj) { //参数为按钮对象
var row = obj.parentNode.parentNode; //按钮所在行
var table = row.parentNode; //按钮所在的表格
var rowIndex = row.rowIndex; //按钮所在的行下标
if (table.rows.length == 1) {
alert("不能再删了，至少保留一行");
} else {
table.deleteRow(rowIndex); //删除当前行
}

}
</script>

——————————————action类代码——————————————

package action;

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.List;

import org.apache.commons.io.IOUtils;
import org.apache.struts2.ServletActionContext;

import com.opensymphony.xwork2.ActionSupport;

public class UploadAction2 extends ActionSupport {

private static final long serialVersionUID = 1L;
private List<File> upload;
private List<String> uploadContentType;
private List<String> uploadFileName;

public String doUpload() throws IOException{
for(int i=0;i<uploadFileName.size();i++){
String savePath=ServletActionContext.getServletContext().getRealPath("/upload/"+this.uploadFileName.get(i));
FileInputStream fis = new FileInputStream(upload.get(i));
FileOutputStream fos = new FileOutputStream(savePath);
System.out.println(upload.get(i));
System.out.println(uploadContentType.get(i));
System.out.println(uploadFileName.get(i));
System.out.println(savePath);
IOUtils.copy(fis, fos);
fos.flush();
fos.close();
fis.close();
}return SUCCESS;
}

public List<File> getUpload() {
return upload;
}

public void setUpload(List<File> upload) {
this.upload = upload;
}

public List<String> getUploadContentType() {
return uploadContentType;