Question

java中怎么判断一个字符串数组中包含某个字符或字符串

Answer 1

/**
     * 判断数组中是否包含某个字符串
     * 包含返回true否则返回false
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        boolean status=false;
        String [] arr={"zhangsan","lisi","wangwu"," zhaoliu"};//字符串数组
        String name="lisi";//判断是否包含的字符串
        for(int i=0;i<arr.length;i++)
        {
            if(arr[i].equals(name))
            {
                status=true;
            }
        }
        System.out.println(status);

    }

Answer 2

String[] ss = {"1","2","3"};
String s = "2";
boolean isContains = Arrays.asList(ss).contains(s);

Answer 3

判断是否单个字符串是否含有字符
String str = "张王aaa赵李";
Pattern p=Pattern.compile("\\w+");//\\w匹配包括下划线的任何单词字符,+一个或者多个
Matcher m=p.matcher(str);
m.find();//true表示包含，false不包含
//字符数组循环一下就好 了

Answer 4

String str="ABC_001";
if(str.indexOf("ABC")!=-1){
System.out.println("包含");
}else{ System.out.println("不包含");
}
数组的话就转换成list 然后list有一个contains方法 之间判断

Answer 5

String[] ss = {"1","2","3"};
String s = "2";
boolean isContains = Arrays.asList(ss).contains(s);

另外可以通过遍历一个个判断
public static void main(String[] args) {
// TODO Auto-generated method stub
boolean status=false;
String [] arr={"zhangsan","lisi","wangwu"," zhaoliu"};//字符串数组
String name="lisi";//判断是否包含的字符串
for(int i=0;i<arr.length;i++)
{
if(arr[i].equals(name))
{
status=true;
}
}
System.out.println(status);

}