
计算题,求解
1个回答
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原式=[(19又5/9-1.32)/(19又5/9-1.32)]÷[(2000×0.7+3.5×0.6)/(2003×0.6)]
=1÷[(2000×0.7+0.7×3)/(2003×0.6)]
=1÷[(2003×0.7)/(2003×0.6)]
=1÷0.7/0.6
=6/7
=1÷[(2000×0.7+0.7×3)/(2003×0.6)]
=1÷[(2003×0.7)/(2003×0.6)]
=1÷0.7/0.6
=6/7
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