画横线式子来的过程
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解:y=2x^2+x+1
=2(x^2+1/2x+1/2)
=2[(x^2+1/2x+(1/4)^2-(1/4)^2+1/2]
=2[(x+1/4)^2-1/16+1/2)
=2[(x+1/4)^2+7/16]
=2(x+1/4)^2+7/8
答:答案是y=2(x+1/4)^2+7/8.
=2(x^2+1/2x+1/2)
=2[(x^2+1/2x+(1/4)^2-(1/4)^2+1/2]
=2[(x+1/4)^2-1/16+1/2)
=2[(x+1/4)^2+7/16]
=2(x+1/4)^2+7/8
答:答案是y=2(x+1/4)^2+7/8.
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