如何用javascript实现一张图片的任意角度旋转 求源码 10
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<!DOCTYPE HTML>
<html>
<head>
<meta charset=UTF-8>
<title>YuGiOh</title>
<style type="text/css">
*{
margin:0;
padding:0;
}
#div {
position: absolute;
top: 50px;
left: 300px;
width: 200px;
height: 200px;
line-height: 200px;
text-align: center;
border: 1px solid black;
background-color:#fd3;
}
</style>
<script type="text/javascript">
var deg = 0;
var rotateHTML5 = function(limit) {
deg += limit;
deg = deg > 360 ? 1 : deg;
div.style['transform'] = div.style['-webkit-transform'] = 'rotate(' + deg + 'deg)';
};
var rotateIE = function(obj) {
var d = !! obj.d ? obj.d : 1;
var r = d * Math.PI / 180;
costheta = Math.cos(r);
sintheta = Math.sin(r);
obj.style.filter = "progid:DXImageTransform.Microsoft.Matrix()";
var item = obj.filters.item(0);
var width = obj.clientWidth;
var height = obj.clientHeight;
item.DX = -width / 2 * costheta + height / 2 * sintheta + width / 2;
item.DY = -width / 2 * sintheta - height / 2 * costheta + height / 2;
item.M11 = costheta;
item.M12 = -sintheta;
item.M21 = sintheta;
item.M22 = costheta;
obj.timer = setTimeout(function() {
var dx = d + 1;
dx = dx > 360 ? 1 : dx;
obj.d = dx;
rotateIE(obj);
}, 30);
};
var start = function() {
if (!/.*MSIE.*/i.test(navigator.userAgent)) {
if ( !! div.interval) {
clearInterval(div.interval);
div.interval = null;
} else {
div.interval = setInterval(function() {
rotateHTML5(1);
}, 30);
}
} else {
if ( !! div.timer) {
clearTimeout(div.timer);
div.timer = null;
} else {
rotateIE(div);
}
}
};
</script>
</head>
<body>
<button onclick="start();">rotate</button>
<div id="div">ROTATE</div>
</body>
</html>
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