Question

C语言编程从5到100之间找出能被5或7整除的数

Answer 1

#include<stdio.h>
void main()
{int i;
for(i=5;i<=100;i++)
{if(i%5==0)
printf("能被5整除的数%d\n",i);
if(i%7==0)
printf("能被7整除的数%d\n",i);
}
}

Answer 2

#include<stdio.h>
void main()
{
int i;
for(i=5;i<=100;i++)
{
if(i%5==0||i%7==0)printf("%d\n",i);
}
}

Answer 3

main()
{
int i=5;
for(i=5;i<=100;i++)
{
if((i%5==0)||(i%7==0))
printf("%d,\n",i);
}
}

Answer 4

#include <stdio.h>
main()
{
int i;
for(i=5;i<=100;i++)
if(i%5==0||i%7==0)
printf("%4d",i);
}

Answer 5

#include <stdio.h>
#include <stdlib.h>

int
main( void )
{
int i;
int j = 0;
int t = 0;
int a[100];

for( i = 5; i < 100; i++ )
if( ( i % 7 == 0 ) || ( i % 5 ) == 0 )
{
a[j] = i;
j++;
}

for( i = 0; i < j; i++ )
{
printf( "%d ", a[i] );
t++;
if( t % 5 == 0 )
printf( "\n" );
}

return EXIT_SUCCESS;
}