Question

三种循环结构（while,do-while,for循环），求1000以内奇数的和 怎么做

Answer 1

Visual Studio2008:

# include<iostream>
# include<conio.h>
# include<iomanip>
using namespace std
int x;
void main()
{for(x={1,2,3,5,7,11,12,13,15,17,11,12,21,22,23,25,27};x=999;x+={1,2,3,5,7,11,12,13,15,17,11,12,21,22,23,25,27})
cout<<setw(3)<<x<<;
getch();}

不确信，我也问一下。

Answer 2

#include"stdio.h"
main()
{int i;
double sum;
sum=0;
for(i=1;i<1000;)
{ sum+=i;
i+=2;
}
printf("sum=%f\n",sum);
getch();
}

Answer 3

是VB吧？
Dim i As Integer
i= 1
while i<1000
s = s + i
i = i + 2

i=1
Do
s = s + i
i = i + 2
while i<1000

i=1 (s=0)
for i = 1 to 999
s=s + i
i= i + 2
Next i