求log2 1-log2 0.105=3.25为什么是怎么算的? 如题
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log2(1)-log2(0.105)
=0-log2(0.105)
=-log2(0.105)
=log2[(0.105)^(-1)]
=log2[(21/200)^(-1)]
=log2[200/21]
=log2[200]-log2[21]
=log2[2*100]-log2[21]
=1+log2[4*25]-log2[21]
=1+2+log2[25/21]
=3+log2[25/21]
=0-log2(0.105)
=-log2(0.105)
=log2[(0.105)^(-1)]
=log2[(21/200)^(-1)]
=log2[200/21]
=log2[200]-log2[21]
=log2[2*100]-log2[21]
=1+log2[4*25]-log2[21]
=1+2+log2[25/21]
=3+log2[25/21]
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