(xy+1)^2+(x+y)(x+y-2xy-2)怎么解啊是因式分解？
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令a=xy,b=x+y
原式=(a+1)²+b(b-2a-2)
=a²+2a+1+b²-2ab-2b
=(a²-2ab+b²)+2a-2b+1
=(a-b)²+2(a-b)+1
=(a-b+1)²
=(xy-x-y+1)²
=[x(y-1)-(y-1)]²
=(y-1)²(x-1)²,5,（xy+1）²-2（xy+1)(x+y)+(x+y)²
=(xy+1-x-y)²
=【（xy-y)-(x-1)]²
=【y(x-1)-(x-1)]²
=（x-1)²（y-1)²,2,如图
爪机党
有点慢
,2,
原式=(a+1)²+b(b-2a-2)
=a²+2a+1+b²-2ab-2b
=(a²-2ab+b²)+2a-2b+1
=(a-b)²+2(a-b)+1
=(a-b+1)²
=(xy-x-y+1)²
=[x(y-1)-(y-1)]²
=(y-1)²(x-1)²,5,（xy+1）²-2（xy+1)(x+y)+(x+y)²
=(xy+1-x-y)²
=【（xy-y)-(x-1)]²
=【y(x-1)-(x-1)]²
=（x-1)²（y-1)²,2,如图
爪机党
有点慢
,2,
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