Question

∫【1~-1】((3x^4)-(2x^2))dx求ŀ

Answer 1

∫【1~-1】((3x^4)-(2x^2))dx
= 2∫【0，1】d(3x^5/5)-(2x^2/3))
=2(3/5-2/3)
=8/15

Answer 2

解:∫(1,-1)[(3x^4)-(2x^2)]dx=∫(-1,1)2x^2dx-∫(-1,1)3x^4dx
=(2/3)x^3I(-1,1)-(3/5)x^5I(-1,1)
=(2/3)[1-(-1)^3]-(3/5)[1-(-1)^5]
=(4/3)-(6/5)
=2/5