Question

√32-4√1/2×√1/8 （1-2√3）（2√3+1）+（2√3+1）²怎么解

拜托

Answer 1

√32-4√1/2×√1/8
=4√2-4√(1/2×1/8)
=4√2-4√(1/16)
=4√2-4×(1/4)
=4√2-1

(1-2√3）（2√3+1）+（2√3+1）²
=1²-(2√3)²+[(2√3)²+2×2√3×1+1²]
=1-12+12+4√3+1
=2+4√3

Answer 2

1.
9(2x+3）²=4（2x-5)
9(2x+3）²-4(2x+3)+32=0
(2x+3）看为一个整体=m
9m²-4m+32=0
△<0 无解
2.x²-（1+根号2）x+根号2=0
（x-1)(x-根号2）=0
x=1或x=根号2