
lingo求解非线性规划
model:sets:d/1..12/:x,y,k;endsetsmax=@sum(d(i):x(i)*y(i));@for(d:@gin(x));@for(d:@mod...
model:
sets:
d/1..12/:x,y,k;
endsets
max=@sum(d(i):x(i)*y(i));
@for(d:@gin(x));
@for(d:@mod(x,5)=0);
x(12)>=20;
y(1)>=13;
k(i)=@sum(d(j) | j#le#i : y(j));
@for(d(i) : (x(i)*x(i)/4+k(i)*k(i))<=325*325);
end
错在哪啊!各位高手帮忙看看啊!提示是
model is ill defined! 展开
sets:
d/1..12/:x,y,k;
endsets
max=@sum(d(i):x(i)*y(i));
@for(d:@gin(x));
@for(d:@mod(x,5)=0);
x(12)>=20;
y(1)>=13;
k(i)=@sum(d(j) | j#le#i : y(j));
@for(d(i) : (x(i)*x(i)/4+k(i)*k(i))<=325*325);
end
错在哪啊!各位高手帮忙看看啊!提示是
model is ill defined! 展开
1个回答
展开全部
model:
sets:
d/1..12/:x,y,k;
endsets
max=@sum(d(i):x(i)*y(i));
@for(d:@gin(x));
@for(d:@mod(x,5)=0);
x(12)>=20;
y(1)>=13;
@for(d(i):k(i)=@sum(d(j) | j#le#i : y(j)));
@for(d(i) : (x(i)*x(i)/4+k(i)*k(i))<=325*325);
end
sets:
d/1..12/:x,y,k;
endsets
max=@sum(d(i):x(i)*y(i));
@for(d:@gin(x));
@for(d:@mod(x,5)=0);
x(12)>=20;
y(1)>=13;
@for(d(i):k(i)=@sum(d(j) | j#le#i : y(j)));
@for(d(i) : (x(i)*x(i)/4+k(i)*k(i))<=325*325);
end
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