Question

请问如何用卡西欧ClassPad300图形计算器解二元二次方程组，如：x^2-y=1,x+5y=9,谢谢！

在Main中输入：solve(x^2-y=1 and x+5y=9,x,y)执行后出现无效语法提示（Invalid Syntax），请把过程写清楚一些，我刚刚学习图形计算器的使用，手里只有一本英文的说明书，看不懂，谢谢各位好心人的帮助！另：哪里能得到该型号计算器的中文说明书啊？谢谢.

Answer 1

请问。。。这个方程有解么。。。
好不容易从CASIO CP330说明书上找到了。。。
http://eblog.cersp.com/userlog5/78304/archives/2007/273355.shtml
u solve
Function: Returns the solution of an equation or inequality.
Syntax: solve (Exp/Eq/Ineq [,variable] [ ) ]
• For this syntax, “Ineq” also includes the ≠ operator.
• “x” is the default when you omit “[,variable]”.
solve (Exp/Eq,variable[, value, lower limit, upper limit] [ ) ]
• This syntax does not support “Ineq”, but the ≠ operator is supported.
• “value” is an initially estimated value.
• This command is valid only for equations and ≠ expressions when “value”
and the items following it are included. In that case, this command returns
an approximate value.
• A true value is returned when you omit “value” and the items following it.
When, however, a true value cannot be obtained, an approximate value is
returned for equations only based on the assumption that value = 0, lower
limit = –
, and upper limit =
.
solve ({Exp-1/Eq-1, ..., Exp-N/Eq-N}, {variable-1, ..., variable-N} [ ) ]
• When “Exp” is the first argument, the equation Exp = 0 is presumed.
Example: To solve ax + b = 0 for x
Menu Item: [Action][Equation/Inequality][solve]
Example: To solve simultaneous linear equations 3x + 4y = 5, 2x – 3y = –8
Menu Item: [Action][Equation/Inequality][solve]

说明：解x+y=1, 2x-y=2
格式：solve({x+y=1,2x-y=2},{x,y})
EXE
LZ提供的式子似乎没法解。。。
我的解：【模拟器中】
solve({x-y=1,x+5y=9},{x,y}
{x=((7)/(3)),y=((4)/(3))}

solve({x^2-y=1,x+5y=9},{x,y}
{x^(2)-y=1,x+5*y=9}【直接出式子了。。。说明解不了。。。】

另。。。没有中文说明书。。。这种东西大多是内部发行的。。。

当然。。。您可以联系一下卡西欧教育资源xx部【具体记不清了。。。】的赵建华课长E-Mail索要。。。

Answer 2

自己上网查或找Q为542361195的人,他会教你的